How to startup application only on schedule?
Clash Royale CLAN TAG#URR8PPP up vote
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I would like to start on boot Slack only when I'm at work (basically, its 10:00 am till 18:00 pm on working days). I do not really want to write custom scripts, I would like to check this in more good way, for example:
But how? My first approach is to use cron's @reboot with date - not looks like its possible. Secondly, I've tried to search for tool, which you pass test string in crontab format and getting error code 1 or 0 back - no luck here.
Could you please point me in right direction?
startup
edited Apr 10 at 14:02
pa4080
12.2k52255
asked Apr 10 at 11:51
Tymur Valiiev
112
add a comment |Â
up vote
2
down vote
favorite
I would like to start on boot Slack only when I'm at work (basically, its 10:00 am till 18:00 pm on working days). I do not really want to write custom scripts, I would like to check this in more good way, for example:
But how? My first approach is to use cron's @reboot with date - not looks like its possible. Secondly, I've tried to search for tool, which you pass test string in crontab format and getting error code 1 or 0 back - no luck here.
Could you please point me in right direction?
startup
edited Apr 10 at 14:02
pa4080
12.2k52255
asked Apr 10 at 11:51
Tymur Valiiev
112
add a comment |Â
up vote
2
down vote
favorite
up vote
2
down vote
favorite
I would like to start on boot Slack only when I'm at work (basically, its 10:00 am till 18:00 pm on working days). I do not really want to write custom scripts, I would like to check this in more good way, for example:
But how? My first approach is to use cron's @reboot with date - not looks like its possible. Secondly, I've tried to search for tool, which you pass test string in crontab format and getting error code 1 or 0 back - no luck here.
Could you please point me in right direction?
startup
edited Apr 10 at 14:02
pa4080
12.2k52255
asked Apr 10 at 11:51
Tymur Valiiev
112
I would like to start on boot Slack only when I'm at work (basically, its 10:00 am till 18:00 pm on working days). I do not really want to write custom scripts, I would like to check this in more good way, for example:
But how? My first approach is to use cron's @reboot with date - not looks like its possible. Secondly, I've tried to search for tool, which you pass test string in crontab format and getting error code 1 or 0 back - no luck here.
Could you please point me in right direction?
startup
startup
edited Apr 10 at 14:02
pa4080
12.2k52255
asked Apr 10 at 11:51
Tymur Valiiev
112
edited Apr 10 at 14:02
pa4080
12.2k52255
asked Apr 10 at 11:51
Tymur Valiiev
112
edited Apr 10 at 14:02
pa4080
12.2k52255
edited Apr 10 at 14:02
pa4080
12.2k52255
edited Apr 10 at 14:02
pa4080
12.2k52255
12.2k52255
asked Apr 10 at 11:51
Tymur Valiiev
112
asked Apr 10 at 11:51
Tymur Valiiev
112
asked Apr 10 at 11:51
Tymur Valiiev
112
112
add a comment |Â
add a comment |Â
1 Answer
1
active
oldest
votes
up vote
1
down vote
The command date +%u will output the day of the week as number. The command date +%k will output the current hour in 24h format. We can use command substitution $() and bash double brackets test [[ to create an appropriate condition:
bash -c '[[ $(date +%u) == [1-5] && $(date +%k) == 1[0-7] ]] && /path/executable'
[1-5]- is a regular expression that describes the working days of the week.1[0-7]- is a regexp that describes the working hours, it will cover from 10:00 to 17:59./path/executableis a synopsis for the command/application that you want to run.Within the expression
[[ <condition-1> && <condition-2> ]], the logical and&&means that both conditions must be fulfilled.
According to the question, you can use the above command within crontab, or with Startup Applications. For couple of reasons I would prefer to use Startup Applications.
answered Apr 10 at 13:38
pa4080
12.2k52255
i think it will work, ill find out tomorrow.
– Tymur Valiiev
Apr 10 at 19:33
@âøüурÃ’ðûøõò, it works in the command line. If there is an issue try to addsleep 15 &&in front of the command - 15 seconds should be enough for the graphical environment to be completely loaded.
– pa4080
Apr 10 at 19:41
Its not working for me. Tried few days, no luck. It works in commandline, but not via "Startup Applications"
– Tymur Valiiev
Apr 16 at 17:59
add a comment |Â
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
The command date +%u will output the day of the week as number. The command date +%k will output the current hour in 24h format. We can use command substitution $() and bash double brackets test [[ to create an appropriate condition:
bash -c '[[ $(date +%u) == [1-5] && $(date +%k) == 1[0-7] ]] && /path/executable'
[1-5]- is a regular expression that describes the working days of the week.1[0-7]- is a regexp that describes the working hours, it will cover from 10:00 to 17:59./path/executableis a synopsis for the command/application that you want to run.Within the expression
[[ <condition-1> && <condition-2> ]], the logical and&&means that both conditions must be fulfilled.
According to the question, you can use the above command within crontab, or with Startup Applications. For couple of reasons I would prefer to use Startup Applications.
answered Apr 10 at 13:38
pa4080
12.2k52255
i think it will work, ill find out tomorrow.
– Tymur Valiiev
Apr 10 at 19:33
@âøüурÃ’ðûøõò, it works in the command line. If there is an issue try to addsleep 15 &&in front of the command - 15 seconds should be enough for the graphical environment to be completely loaded.
– pa4080
Apr 10 at 19:41
Its not working for me. Tried few days, no luck. It works in commandline, but not via "Startup Applications"
– Tymur Valiiev
Apr 16 at 17:59
add a comment |Â
up vote
1
down vote
The command date +%u will output the day of the week as number. The command date +%k will output the current hour in 24h format. We can use command substitution $() and bash double brackets test [[ to create an appropriate condition:
bash -c '[[ $(date +%u) == [1-5] && $(date +%k) == 1[0-7] ]] && /path/executable'
[1-5]- is a regular expression that describes the working days of the week.1[0-7]- is a regexp that describes the working hours, it will cover from 10:00 to 17:59./path/executableis a synopsis for the command/application that you want to run.Within the expression
[[ <condition-1> && <condition-2> ]], the logical and&&means that both conditions must be fulfilled.
According to the question, you can use the above command within crontab, or with Startup Applications. For couple of reasons I would prefer to use Startup Applications.
answered Apr 10 at 13:38
pa4080
12.2k52255
i think it will work, ill find out tomorrow.
– Tymur Valiiev
Apr 10 at 19:33
@âøüурÃ’ðûøõò, it works in the command line. If there is an issue try to addsleep 15 &&in front of the command - 15 seconds should be enough for the graphical environment to be completely loaded.
– pa4080
Apr 10 at 19:41
Its not working for me. Tried few days, no luck. It works in commandline, but not via "Startup Applications"
– Tymur Valiiev
Apr 16 at 17:59
add a comment |Â
up vote
1
down vote
up vote
1
down vote
The command date +%u will output the day of the week as number. The command date +%k will output the current hour in 24h format. We can use command substitution $() and bash double brackets test [[ to create an appropriate condition:
bash -c '[[ $(date +%u) == [1-5] && $(date +%k) == 1[0-7] ]] && /path/executable'
[1-5]- is a regular expression that describes the working days of the week.1[0-7]- is a regexp that describes the working hours, it will cover from 10:00 to 17:59./path/executableis a synopsis for the command/application that you want to run.Within the expression
[[ <condition-1> && <condition-2> ]], the logical and&&means that both conditions must be fulfilled.
According to the question, you can use the above command within crontab, or with Startup Applications. For couple of reasons I would prefer to use Startup Applications.
answered Apr 10 at 13:38
pa4080
12.2k52255
The command date +%u will output the day of the week as number. The command date +%k will output the current hour in 24h format. We can use command substitution $() and bash double brackets test [[ to create an appropriate condition:
bash -c '[[ $(date +%u) == [1-5] && $(date +%k) == 1[0-7] ]] && /path/executable'
[1-5]- is a regular expression that describes the working days of the week.1[0-7]- is a regexp that describes the working hours, it will cover from 10:00 to 17:59./path/executableis a synopsis for the command/application that you want to run.Within the expression
[[ <condition-1> && <condition-2> ]], the logical and&&means that both conditions must be fulfilled.
According to the question, you can use the above command within crontab, or with Startup Applications. For couple of reasons I would prefer to use Startup Applications.
answered Apr 10 at 13:38
pa4080
12.2k52255
edited Apr 10 at 14:55
answered Apr 10 at 13:38
pa4080
12.2k52255
answered Apr 10 at 13:38
pa4080
12.2k52255
answered Apr 10 at 13:38
pa4080
12.2k52255
12.2k52255
i think it will work, ill find out tomorrow.
– Tymur Valiiev
Apr 10 at 19:33
@âøüурÃ’ðûøõò, it works in the command line. If there is an issue try to addsleep 15 &&in front of the command - 15 seconds should be enough for the graphical environment to be completely loaded.
– pa4080
Apr 10 at 19:41
Its not working for me. Tried few days, no luck. It works in commandline, but not via "Startup Applications"
– Tymur Valiiev
Apr 16 at 17:59
add a comment |Â
i think it will work, ill find out tomorrow.
– Tymur Valiiev
Apr 10 at 19:33
@âøüурÃ’ðûøõò, it works in the command line. If there is an issue try to addsleep 15 &&in front of the command - 15 seconds should be enough for the graphical environment to be completely loaded.
– pa4080
Apr 10 at 19:41
Its not working for me. Tried few days, no luck. It works in commandline, but not via "Startup Applications"
– Tymur Valiiev
Apr 16 at 17:59
i think it will work, ill find out tomorrow.
– Tymur Valiiev
Apr 10 at 19:33
i think it will work, ill find out tomorrow.
– Tymur Valiiev
Apr 10 at 19:33
@âøüурÃ’ðûøõò, it works in the command line. If there is an issue try to add
sleep 15 && in front of the command - 15 seconds should be enough for the graphical environment to be completely loaded.– pa4080
Apr 10 at 19:41
@âøüурÃ’ðûøõò, it works in the command line. If there is an issue try to add
sleep 15 && in front of the command - 15 seconds should be enough for the graphical environment to be completely loaded.– pa4080
Apr 10 at 19:41
Its not working for me. Tried few days, no luck. It works in commandline, but not via "Startup Applications"
– Tymur Valiiev
Apr 16 at 17:59
Its not working for me. Tried few days, no luck. It works in commandline, but not via "Startup Applications"
– Tymur Valiiev
Apr 16 at 17:59
add a comment |Â
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