Grandpa's crazy math. Another Grandpa Mystery
![Creative The name of the picture](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgO9GURib1T8z7lCwjOGLQaGtrueEthgQ8LO42ZX8cOfTqDK4jvDDpKkLFwf2J49kYCMNW7d4ABih_XCb_2UXdq5fPJDkoyg7-8g_YfRUot-XnaXkNYycsNp7lA5_TW9td0FFpLQ2APzKcZ/s1600/1.jpg)
![Creative The name of the picture](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhYQ0N5W1qAOxLP7t7iOM6O6AzbZnkXUy16s7P_CWfOb5UbTQY_aDsc727chyphenhyphen5W4IppVNernMMQeaUFTB_rFzAd95_CDt-tnwN-nBx6JyUp2duGjPaL5-VgNO41AVsA_vu30EJcipdDG409/s400/Clash+Royale+CLAN+TAG%2523URR8PPP.png)
up vote
15
down vote
favorite
Grandpa says : " Bit of a stretch but--
2.72 = 1000 x 10000
Is he crazy or genius?
riddle
add a comment |Â
up vote
15
down vote
favorite
Grandpa says : " Bit of a stretch but--
2.72 = 1000 x 10000
Is he crazy or genius?
riddle
add a comment |Â
up vote
15
down vote
favorite
up vote
15
down vote
favorite
Grandpa says : " Bit of a stretch but--
2.72 = 1000 x 10000
Is he crazy or genius?
riddle
Grandpa says : " Bit of a stretch but--
2.72 = 1000 x 10000
Is he crazy or genius?
riddle
asked yesterday
DEEM
3,360969
3,360969
add a comment |Â
add a comment |Â
1 Answer
1
active
oldest
votes
up vote
29
down vote
accepted
2.72
e = 2.718281828... ~ 2.72
1000 x 10000
M = 1000 and C= 100 in Roman numerals so $c^2 = 10000$
Relatively speaking I think Granpda is a genius
$E = mc^2$
3
Its all relative, isnt it @Tom?
â DEEM
23 hours ago
7
(Grumblemumblegrumblecapitalizationmattersinphysicsgrumblemumble)
â Bass
16 hours ago
4
@Bass, one for you: $f = mu n$
â Tom
16 hours ago
But not in my silly riddles @Bass. LOL
â DEEM
12 hours ago
add a comment |Â
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
29
down vote
accepted
2.72
e = 2.718281828... ~ 2.72
1000 x 10000
M = 1000 and C= 100 in Roman numerals so $c^2 = 10000$
Relatively speaking I think Granpda is a genius
$E = mc^2$
3
Its all relative, isnt it @Tom?
â DEEM
23 hours ago
7
(Grumblemumblegrumblecapitalizationmattersinphysicsgrumblemumble)
â Bass
16 hours ago
4
@Bass, one for you: $f = mu n$
â Tom
16 hours ago
But not in my silly riddles @Bass. LOL
â DEEM
12 hours ago
add a comment |Â
up vote
29
down vote
accepted
2.72
e = 2.718281828... ~ 2.72
1000 x 10000
M = 1000 and C= 100 in Roman numerals so $c^2 = 10000$
Relatively speaking I think Granpda is a genius
$E = mc^2$
3
Its all relative, isnt it @Tom?
â DEEM
23 hours ago
7
(Grumblemumblegrumblecapitalizationmattersinphysicsgrumblemumble)
â Bass
16 hours ago
4
@Bass, one for you: $f = mu n$
â Tom
16 hours ago
But not in my silly riddles @Bass. LOL
â DEEM
12 hours ago
add a comment |Â
up vote
29
down vote
accepted
up vote
29
down vote
accepted
2.72
e = 2.718281828... ~ 2.72
1000 x 10000
M = 1000 and C= 100 in Roman numerals so $c^2 = 10000$
Relatively speaking I think Granpda is a genius
$E = mc^2$
2.72
e = 2.718281828... ~ 2.72
1000 x 10000
M = 1000 and C= 100 in Roman numerals so $c^2 = 10000$
Relatively speaking I think Granpda is a genius
$E = mc^2$
answered 23 hours ago
![](https://i.stack.imgur.com/dNIHv.png?s=32&g=1)
![](https://i.stack.imgur.com/dNIHv.png?s=32&g=1)
Tom
21.6k278129
21.6k278129
3
Its all relative, isnt it @Tom?
â DEEM
23 hours ago
7
(Grumblemumblegrumblecapitalizationmattersinphysicsgrumblemumble)
â Bass
16 hours ago
4
@Bass, one for you: $f = mu n$
â Tom
16 hours ago
But not in my silly riddles @Bass. LOL
â DEEM
12 hours ago
add a comment |Â
3
Its all relative, isnt it @Tom?
â DEEM
23 hours ago
7
(Grumblemumblegrumblecapitalizationmattersinphysicsgrumblemumble)
â Bass
16 hours ago
4
@Bass, one for you: $f = mu n$
â Tom
16 hours ago
But not in my silly riddles @Bass. LOL
â DEEM
12 hours ago
3
3
Its all relative, isnt it @Tom?
â DEEM
23 hours ago
Its all relative, isnt it @Tom?
â DEEM
23 hours ago
7
7
(Grumblemumblegrumblecapitalizationmattersinphysicsgrumblemumble)
â Bass
16 hours ago
(Grumblemumblegrumblecapitalizationmattersinphysicsgrumblemumble)
â Bass
16 hours ago
4
4
@Bass, one for you: $f = mu n$
â Tom
16 hours ago
@Bass, one for you: $f = mu n$
â Tom
16 hours ago
But not in my silly riddles @Bass. LOL
â DEEM
12 hours ago
But not in my silly riddles @Bass. LOL
â DEEM
12 hours ago
add a comment |Â
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
var $window = $(window),
onScroll = function(e)
var $elem = $('.new-login-left'),
docViewTop = $window.scrollTop(),
docViewBottom = docViewTop + $window.height(),
elemTop = $elem.offset().top,
elemBottom = elemTop + $elem.height();
if ((docViewTop elemBottom))
StackExchange.using('gps', function() StackExchange.gps.track('embedded_signup_form.view', location: 'question_page' ); );
$window.unbind('scroll', onScroll);
;
$window.on('scroll', onScroll);
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fpuzzling.stackexchange.com%2fquestions%2f68939%2fgrandpas-crazy-math-another-grandpa-mystery%23new-answer', 'question_page');
);
Post as a guest
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
var $window = $(window),
onScroll = function(e)
var $elem = $('.new-login-left'),
docViewTop = $window.scrollTop(),
docViewBottom = docViewTop + $window.height(),
elemTop = $elem.offset().top,
elemBottom = elemTop + $elem.height();
if ((docViewTop elemBottom))
StackExchange.using('gps', function() StackExchange.gps.track('embedded_signup_form.view', location: 'question_page' ); );
$window.unbind('scroll', onScroll);
;
$window.on('scroll', onScroll);
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
var $window = $(window),
onScroll = function(e)
var $elem = $('.new-login-left'),
docViewTop = $window.scrollTop(),
docViewBottom = docViewTop + $window.height(),
elemTop = $elem.offset().top,
elemBottom = elemTop + $elem.height();
if ((docViewTop elemBottom))
StackExchange.using('gps', function() StackExchange.gps.track('embedded_signup_form.view', location: 'question_page' ); );
$window.unbind('scroll', onScroll);
;
$window.on('scroll', onScroll);
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
var $window = $(window),
onScroll = function(e)
var $elem = $('.new-login-left'),
docViewTop = $window.scrollTop(),
docViewBottom = docViewTop + $window.height(),
elemTop = $elem.offset().top,
elemBottom = elemTop + $elem.height();
if ((docViewTop elemBottom))
StackExchange.using('gps', function() StackExchange.gps.track('embedded_signup_form.view', location: 'question_page' ); );
$window.unbind('scroll', onScroll);
;
$window.on('scroll', onScroll);
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password