How to assign variable to PROMPT_COMMAND


up vote
0
down vote
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How can I increment a variable assigning its value to PROMPT_COMMAND variable?
Inside .bashrc I created variable a
and assigned value to 0
and then added this
a=0
PROMPT_COMMAND=`((a++))`
When I echo PROMPT_COMMAND it shows that it is empty.
bash prompt
add a comment |Â
up vote
0
down vote
favorite
How can I increment a variable assigning its value to PROMPT_COMMAND variable?
Inside .bashrc I created variable a
and assigned value to 0
and then added this
a=0
PROMPT_COMMAND=`((a++))`
When I echo PROMPT_COMMAND it shows that it is empty.
bash prompt
PROMPT_COMMAND
is empty in your code because((a++))
doesn't print anything, only incrementsa
.
â wjandrea
May 22 at 16:18
add a comment |Â
up vote
0
down vote
favorite
up vote
0
down vote
favorite
How can I increment a variable assigning its value to PROMPT_COMMAND variable?
Inside .bashrc I created variable a
and assigned value to 0
and then added this
a=0
PROMPT_COMMAND=`((a++))`
When I echo PROMPT_COMMAND it shows that it is empty.
bash prompt
How can I increment a variable assigning its value to PROMPT_COMMAND variable?
Inside .bashrc I created variable a
and assigned value to 0
and then added this
a=0
PROMPT_COMMAND=`((a++))`
When I echo PROMPT_COMMAND it shows that it is empty.
bash prompt
edited May 22 at 16:16


wjandrea
7,14142155
7,14142155
asked Apr 30 at 12:32


Andrew
1824
1824
PROMPT_COMMAND
is empty in your code because((a++))
doesn't print anything, only incrementsa
.
â wjandrea
May 22 at 16:18
add a comment |Â
PROMPT_COMMAND
is empty in your code because((a++))
doesn't print anything, only incrementsa
.
â wjandrea
May 22 at 16:18
PROMPT_COMMAND
is empty in your code because ((a++))
doesn't print anything, only increments a
.â wjandrea
May 22 at 16:18
PROMPT_COMMAND
is empty in your code because ((a++))
doesn't print anything, only increments a
.â wjandrea
May 22 at 16:18
add a comment |Â
1 Answer
1
active
oldest
votes
up vote
1
down vote
accepted
It works with
a=0
PROMPT_COMMAND='echo -n $((a++))'
after you open a new shell (or source .bashrc by calling . ~/.bashrc
.
add a comment |Â
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
It works with
a=0
PROMPT_COMMAND='echo -n $((a++))'
after you open a new shell (or source .bashrc by calling . ~/.bashrc
.
add a comment |Â
up vote
1
down vote
accepted
It works with
a=0
PROMPT_COMMAND='echo -n $((a++))'
after you open a new shell (or source .bashrc by calling . ~/.bashrc
.
add a comment |Â
up vote
1
down vote
accepted
up vote
1
down vote
accepted
It works with
a=0
PROMPT_COMMAND='echo -n $((a++))'
after you open a new shell (or source .bashrc by calling . ~/.bashrc
.
It works with
a=0
PROMPT_COMMAND='echo -n $((a++))'
after you open a new shell (or source .bashrc by calling . ~/.bashrc
.
answered Apr 30 at 13:16


muclux
2,1231521
2,1231521
add a comment |Â
add a comment |Â
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PROMPT_COMMAND
is empty in your code because((a++))
doesn't print anything, only incrementsa
.â wjandrea
May 22 at 16:18