Display terminal command result in Desktop notification

up vote
5
down vote

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I need to display the result of a terminal command in notification.

Notifications can be triggered by running:

notify-send "Notification message"

The command I have is:

sudo /opt/lampp/xampp start

which shows the following result in terminal:

Starting XAMPP for Linux 5.6.20-0...
XAMPP: Starting Apache...already running.
XAMPP: Starting MySQL...already running.
XAMPP: Starting ProFTPD...already running.

I want this result to be displayed in notification just like "Notification message" is displayed with notify-send.

Thanks!

edited Apr 19 at 21:22

Zanna

48k13119228

asked Apr 14 at 8:28

M. Zeeshan

283

add a commentÂ |Â

up vote
5
down vote

favorite

I need to display the result of a terminal command in notification.

Notifications can be triggered by running:

notify-send "Notification message"

The command I have is:

sudo /opt/lampp/xampp start

which shows the following result in terminal:

Starting XAMPP for Linux 5.6.20-0...
XAMPP: Starting Apache...already running.
XAMPP: Starting MySQL...already running.
XAMPP: Starting ProFTPD...already running.

I want this result to be displayed in notification just like "Notification message" is displayed with notify-send.

Thanks!

edited Apr 19 at 21:22

Zanna

48k13119228

asked Apr 14 at 8:28

M. Zeeshan

283

add a commentÂ |Â

up vote
5
down vote

favorite

I need to display the result of a terminal command in notification.

Notifications can be triggered by running:

notify-send "Notification message"

The command I have is:

sudo /opt/lampp/xampp start

which shows the following result in terminal:

Starting XAMPP for Linux 5.6.20-0...
XAMPP: Starting Apache...already running.
XAMPP: Starting MySQL...already running.
XAMPP: Starting ProFTPD...already running.

I want this result to be displayed in notification just like "Notification message" is displayed with notify-send.

Thanks!

edited Apr 19 at 21:22

Zanna

48k13119228

asked Apr 14 at 8:28

M. Zeeshan

283

I need to display the result of a terminal command in notification.

Notifications can be triggered by running:

notify-send "Notification message"

The command I have is:

sudo /opt/lampp/xampp start

which shows the following result in terminal:

Starting XAMPP for Linux 5.6.20-0...
XAMPP: Starting Apache...already running.
XAMPP: Starting MySQL...already running.
XAMPP: Starting ProFTPD...already running.

I want this result to be displayed in notification just like "Notification message" is displayed with notify-send.

Thanks!

command-line gnome-terminal notification notify-send

edited Apr 19 at 21:22

Zanna

48k13119228

asked Apr 14 at 8:28

M. Zeeshan

283

edited Apr 19 at 21:22

Zanna

48k13119228

asked Apr 14 at 8:28

M. Zeeshan

283

edited Apr 19 at 21:22

Zanna

48k13119228

edited Apr 19 at 21:22

Zanna

48k13119228

edited Apr 19 at 21:22

Zanna

48k13119228

asked Apr 14 at 8:28

M. Zeeshan

283

asked Apr 14 at 8:28

M. Zeeshan

283

asked Apr 14 at 8:28

M. Zeeshan

283

add a commentÂ |Â

1 Answer
1

active

oldest

votes

up vote
8
down vote

accepted

In most cases you can use notify-send with command substitution $(). For example:

notify-send "XAMP Start" "$(sudo /opt/lampp/xampp start)"

Inside a scrip you can use a function to wrap the entire output:

#!/bin/bash
main() echo "Line 1"; echo "Line 2"; echo "Line 3"; 
notify-send "Script output" "$(main)"

If you need to run that function with sudo:

notify-send "Script output" "$(sudo bash -c "$(declare -f main); main")"

edited Apr 15 at 7:07

answered Apr 14 at 8:42

pa4080

12.2k52255

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1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

up vote
8
down vote

accepted

In most cases you can use notify-send with command substitution $(). For example:

notify-send "XAMP Start" "$(sudo /opt/lampp/xampp start)"

Inside a scrip you can use a function to wrap the entire output:

#!/bin/bash
main() echo "Line 1"; echo "Line 2"; echo "Line 3"; 
notify-send "Script output" "$(main)"

If you need to run that function with sudo:

notify-send "Script output" "$(sudo bash -c "$(declare -f main); main")"

edited Apr 15 at 7:07

answered Apr 14 at 8:42

pa4080

12.2k52255

add a commentÂ |Â

up vote
8
down vote

accepted

In most cases you can use notify-send with command substitution $(). For example:

notify-send "XAMP Start" "$(sudo /opt/lampp/xampp start)"

Inside a scrip you can use a function to wrap the entire output:

#!/bin/bash
main() echo "Line 1"; echo "Line 2"; echo "Line 3"; 
notify-send "Script output" "$(main)"

If you need to run that function with sudo:

notify-send "Script output" "$(sudo bash -c "$(declare -f main); main")"

edited Apr 15 at 7:07

answered Apr 14 at 8:42

pa4080

12.2k52255

add a commentÂ |Â

up vote
8
down vote

accepted

In most cases you can use notify-send with command substitution $(). For example:

notify-send "XAMP Start" "$(sudo /opt/lampp/xampp start)"

Inside a scrip you can use a function to wrap the entire output:

#!/bin/bash
main() echo "Line 1"; echo "Line 2"; echo "Line 3"; 
notify-send "Script output" "$(main)"

If you need to run that function with sudo:

notify-send "Script output" "$(sudo bash -c "$(declare -f main); main")"

edited Apr 15 at 7:07

answered Apr 14 at 8:42

pa4080

12.2k52255

In most cases you can use notify-send with command substitution $(). For example:

notify-send "XAMP Start" "$(sudo /opt/lampp/xampp start)"

Inside a scrip you can use a function to wrap the entire output:

#!/bin/bash
main() echo "Line 1"; echo "Line 2"; echo "Line 3"; 
notify-send "Script output" "$(main)"

If you need to run that function with sudo:

notify-send "Script output" "$(sudo bash -c "$(declare -f main); main")"

edited Apr 15 at 7:07

answered Apr 14 at 8:42

pa4080

12.2k52255

edited Apr 15 at 7:07

answered Apr 14 at 8:42

pa4080

12.2k52255

answered Apr 14 at 8:42

pa4080

12.2k52255

answered Apr 14 at 8:42

pa4080

12.2k52255

add a commentÂ |Â

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