Can not echo entire line to file
Clash Royale CLAN TAG#URR8PPP up vote
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I can not figure out how to get the following line echoed to a file.
Only part of it makes it into the file.
echo perl -e "printf("%.1lf%%n", ($reserved_block_count * 100.0 ) / $block_count);">>Show_Percent_Reserved_Blocks.sh
When I run the script below this, I get
andyk_~/Downloads$ Show_Percent_Reserved_Blocks.sh
/home/andy/bin/Show_Percent_Reserved_Blocks.sh: line 2: Block: command not found
/home/andy/bin/Show_Percent_Reserved_Blocks.sh: line 3: Reserved: command not found
syntax error at -e line 1, near "/ )"
Execution of -e aborted due to compilation errors.
#!/bin/bash
Block count: 421958912
Reserved block count: 4219589
perl -e "printf("%.1lf%%n", ($reserved_block_count * 100.0 ) / $block_count);"
command-line bash
edited Jun 11 at 21:59
dadexix86
5,3622492
asked Jun 11 at 21:03
fixit7
435316
add a comment |Â
up vote
1
down vote
favorite
I can not figure out how to get the following line echoed to a file.
Only part of it makes it into the file.
echo perl -e "printf("%.1lf%%n", ($reserved_block_count * 100.0 ) / $block_count);">>Show_Percent_Reserved_Blocks.sh
When I run the script below this, I get
andyk_~/Downloads$ Show_Percent_Reserved_Blocks.sh
/home/andy/bin/Show_Percent_Reserved_Blocks.sh: line 2: Block: command not found
/home/andy/bin/Show_Percent_Reserved_Blocks.sh: line 3: Reserved: command not found
syntax error at -e line 1, near "/ )"
Execution of -e aborted due to compilation errors.
#!/bin/bash
Block count: 421958912
Reserved block count: 4219589
perl -e "printf("%.1lf%%n", ($reserved_block_count * 100.0 ) / $block_count);"
command-line bash
edited Jun 11 at 21:59
dadexix86
5,3622492
asked Jun 11 at 21:03
fixit7
435316
1
Which part makes it into the file? Please edit the question to clarify.
– wjandrea
Jun 11 at 21:16
1
Your edits seem to be about different issues, namely that you've got two non-command lines in the file, and a syntax error in the Perl command. Please ask new question, and make sure to clarify what you're expecting to happen.
– wjandrea
Jun 12 at 1:21
add a comment |Â
up vote
1
down vote
favorite
up vote
1
down vote
favorite
I can not figure out how to get the following line echoed to a file.
Only part of it makes it into the file.
echo perl -e "printf("%.1lf%%n", ($reserved_block_count * 100.0 ) / $block_count);">>Show_Percent_Reserved_Blocks.sh
When I run the script below this, I get
andyk_~/Downloads$ Show_Percent_Reserved_Blocks.sh
/home/andy/bin/Show_Percent_Reserved_Blocks.sh: line 2: Block: command not found
/home/andy/bin/Show_Percent_Reserved_Blocks.sh: line 3: Reserved: command not found
syntax error at -e line 1, near "/ )"
Execution of -e aborted due to compilation errors.
#!/bin/bash
Block count: 421958912
Reserved block count: 4219589
perl -e "printf("%.1lf%%n", ($reserved_block_count * 100.0 ) / $block_count);"
command-line bash
edited Jun 11 at 21:59
dadexix86
5,3622492
asked Jun 11 at 21:03
fixit7
435316
I can not figure out how to get the following line echoed to a file.
Only part of it makes it into the file.
echo perl -e "printf("%.1lf%%n", ($reserved_block_count * 100.0 ) / $block_count);">>Show_Percent_Reserved_Blocks.sh
When I run the script below this, I get
andyk_~/Downloads$ Show_Percent_Reserved_Blocks.sh
/home/andy/bin/Show_Percent_Reserved_Blocks.sh: line 2: Block: command not found
/home/andy/bin/Show_Percent_Reserved_Blocks.sh: line 3: Reserved: command not found
syntax error at -e line 1, near "/ )"
Execution of -e aborted due to compilation errors.
#!/bin/bash
Block count: 421958912
Reserved block count: 4219589
perl -e "printf("%.1lf%%n", ($reserved_block_count * 100.0 ) / $block_count);"
command-line bash
edited Jun 11 at 21:59
dadexix86
5,3622492
asked Jun 11 at 21:03
fixit7
435316
edited Jun 11 at 21:59
dadexix86
5,3622492
edited Jun 11 at 21:59
dadexix86
5,3622492
edited Jun 11 at 21:59
dadexix86
5,3622492
5,3622492
asked Jun 11 at 21:03
fixit7
435316
asked Jun 11 at 21:03
fixit7
435316
asked Jun 11 at 21:03
fixit7
435316
435316
1
Which part makes it into the file? Please edit the question to clarify.
– wjandrea
Jun 11 at 21:16
1
Your edits seem to be about different issues, namely that you've got two non-command lines in the file, and a syntax error in the Perl command. Please ask new question, and make sure to clarify what you're expecting to happen.
– wjandrea
Jun 12 at 1:21
add a comment |Â
1
Which part makes it into the file? Please edit the question to clarify.
– wjandrea
Jun 11 at 21:16
1
Your edits seem to be about different issues, namely that you've got two non-command lines in the file, and a syntax error in the Perl command. Please ask new question, and make sure to clarify what you're expecting to happen.
– wjandrea
Jun 12 at 1:21
1
1
Which part makes it into the file? Please edit the question to clarify.
– wjandrea
Jun 11 at 21:16
Which part makes it into the file? Please edit the question to clarify.
– wjandrea
Jun 11 at 21:16
1
1
Your edits seem to be about different issues, namely that you've got two non-command lines in the file, and a syntax error in the Perl command. Please ask new question, and make sure to clarify what you're expecting to happen.
– wjandrea
Jun 12 at 1:21
Your edits seem to be about different issues, namely that you've got two non-command lines in the file, and a syntax error in the Perl command. Please ask new question, and make sure to clarify what you're expecting to happen.
– wjandrea
Jun 12 at 1:21
add a comment |Â
1 Answer
1
active
oldest
votes
up vote
5
down vote
accepted
The problem is that as you've used double quotes, the variable references ($reserved_block_count, $block_count) are being expanded in the current (invoking) shell environment; you need to quote the whole thing with single quotes around:
echo 'perl -e "printf("%.1lf%%n", ($reserved_block_count * 100.0 ) / $block_count);"' >>Show_Percent_Reserved_Blocks.sh
answered Jun 11 at 21:07
heemayl
63.5k8126202
add a comment |Â
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
5
down vote
accepted
The problem is that as you've used double quotes, the variable references ($reserved_block_count, $block_count) are being expanded in the current (invoking) shell environment; you need to quote the whole thing with single quotes around:
echo 'perl -e "printf("%.1lf%%n", ($reserved_block_count * 100.0 ) / $block_count);"' >>Show_Percent_Reserved_Blocks.sh
answered Jun 11 at 21:07
heemayl
63.5k8126202
add a comment |Â
up vote
5
down vote
accepted
The problem is that as you've used double quotes, the variable references ($reserved_block_count, $block_count) are being expanded in the current (invoking) shell environment; you need to quote the whole thing with single quotes around:
echo 'perl -e "printf("%.1lf%%n", ($reserved_block_count * 100.0 ) / $block_count);"' >>Show_Percent_Reserved_Blocks.sh
answered Jun 11 at 21:07
heemayl
63.5k8126202
add a comment |Â
up vote
5
down vote
accepted
up vote
5
down vote
accepted
The problem is that as you've used double quotes, the variable references ($reserved_block_count, $block_count) are being expanded in the current (invoking) shell environment; you need to quote the whole thing with single quotes around:
echo 'perl -e "printf("%.1lf%%n", ($reserved_block_count * 100.0 ) / $block_count);"' >>Show_Percent_Reserved_Blocks.sh
answered Jun 11 at 21:07
heemayl
63.5k8126202
The problem is that as you've used double quotes, the variable references ($reserved_block_count, $block_count) are being expanded in the current (invoking) shell environment; you need to quote the whole thing with single quotes around:
echo 'perl -e "printf("%.1lf%%n", ($reserved_block_count * 100.0 ) / $block_count);"' >>Show_Percent_Reserved_Blocks.sh
answered Jun 11 at 21:07
heemayl
63.5k8126202
answered Jun 11 at 21:07
heemayl
63.5k8126202
answered Jun 11 at 21:07
heemayl
63.5k8126202
answered Jun 11 at 21:07
heemayl
63.5k8126202
63.5k8126202
add a comment |Â
add a comment |Â
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1
Which part makes it into the file? Please edit the question to clarify.
– wjandrea
Jun 11 at 21:16
1
Your edits seem to be about different issues, namely that you've got two non-command lines in the file, and a syntax error in the Perl command. Please ask new question, and make sure to clarify what you're expecting to happen.
– wjandrea
Jun 12 at 1:21