How to get program to output a command to the ubuntu command line just as if i had typed it
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I have a program dbot that works in the ubuntu command line. If from its directory called dbot I type into the command line from my keyboard " ./dbot.sh any command " it works and does what i want.
So this works ~/dbot$ ./dbot.sh anycommand
I am a beginner and have written a python 3 program tragic.py that is in the same directory called dbot.
If from the ubuntu command line I run tragic.py in the background by ~/dbot$ python3 tragic.py & then if I copy and paste ./dbot.sh anycommand then it works and dbot does what i want. It has to be in the background or the command will not work when pasted so I am using &.
However I want my python program tragic.py to print out onto the command line ./dbot.sh anycommand so that the command gets issued to dbot just as if I had typed it or pasted it. However it does not work either in the background or foreground.
I have tried using a normal print statement and sys.stdout.write() both with and with out sys.stdout.flush() but with no luck
How can I get dbot to respond to the command printed by tragic.py in the ubuntu command line. I dont understand why when I type it or paste it then it works but not when tragic.py prints it or outputs it with sys.stdout.write
command-line python
asked Mar 18 at 2:03
ethertec
31
add a comment |Â
up vote
0
down vote
favorite
I have a program dbot that works in the ubuntu command line. If from its directory called dbot I type into the command line from my keyboard " ./dbot.sh any command " it works and does what i want.
So this works ~/dbot$ ./dbot.sh anycommand
I am a beginner and have written a python 3 program tragic.py that is in the same directory called dbot.
If from the ubuntu command line I run tragic.py in the background by ~/dbot$ python3 tragic.py & then if I copy and paste ./dbot.sh anycommand then it works and dbot does what i want. It has to be in the background or the command will not work when pasted so I am using &.
However I want my python program tragic.py to print out onto the command line ./dbot.sh anycommand so that the command gets issued to dbot just as if I had typed it or pasted it. However it does not work either in the background or foreground.
I have tried using a normal print statement and sys.stdout.write() both with and with out sys.stdout.flush() but with no luck
How can I get dbot to respond to the command printed by tragic.py in the ubuntu command line. I dont understand why when I type it or paste it then it works but not when tragic.py prints it or outputs it with sys.stdout.write
command-line python
asked Mar 18 at 2:03
ethertec
31
Some options for accomplishing this with various tools are discussed here.
– John1024
Mar 18 at 4:06
Are you talking about Command Substitution? As in./dbot.sh $(python3 tragic.py)?
– PerlDuck
Mar 18 at 10:28
add a comment |Â
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I have a program dbot that works in the ubuntu command line. If from its directory called dbot I type into the command line from my keyboard " ./dbot.sh any command " it works and does what i want.
So this works ~/dbot$ ./dbot.sh anycommand
I am a beginner and have written a python 3 program tragic.py that is in the same directory called dbot.
If from the ubuntu command line I run tragic.py in the background by ~/dbot$ python3 tragic.py & then if I copy and paste ./dbot.sh anycommand then it works and dbot does what i want. It has to be in the background or the command will not work when pasted so I am using &.
However I want my python program tragic.py to print out onto the command line ./dbot.sh anycommand so that the command gets issued to dbot just as if I had typed it or pasted it. However it does not work either in the background or foreground.
I have tried using a normal print statement and sys.stdout.write() both with and with out sys.stdout.flush() but with no luck
How can I get dbot to respond to the command printed by tragic.py in the ubuntu command line. I dont understand why when I type it or paste it then it works but not when tragic.py prints it or outputs it with sys.stdout.write
command-line python
asked Mar 18 at 2:03
ethertec
31
I have a program dbot that works in the ubuntu command line. If from its directory called dbot I type into the command line from my keyboard " ./dbot.sh any command " it works and does what i want.
So this works ~/dbot$ ./dbot.sh anycommand
I am a beginner and have written a python 3 program tragic.py that is in the same directory called dbot.
If from the ubuntu command line I run tragic.py in the background by ~/dbot$ python3 tragic.py & then if I copy and paste ./dbot.sh anycommand then it works and dbot does what i want. It has to be in the background or the command will not work when pasted so I am using &.
However I want my python program tragic.py to print out onto the command line ./dbot.sh anycommand so that the command gets issued to dbot just as if I had typed it or pasted it. However it does not work either in the background or foreground.
I have tried using a normal print statement and sys.stdout.write() both with and with out sys.stdout.flush() but with no luck
How can I get dbot to respond to the command printed by tragic.py in the ubuntu command line. I dont understand why when I type it or paste it then it works but not when tragic.py prints it or outputs it with sys.stdout.write
command-line python
command-line python
asked Mar 18 at 2:03
ethertec
31
asked Mar 18 at 2:03
ethertec
31
asked Mar 18 at 2:03
ethertec
31
asked Mar 18 at 2:03
ethertec
31
asked Mar 18 at 2:03
ethertec
31
31
Some options for accomplishing this with various tools are discussed here.
– John1024
Mar 18 at 4:06
Are you talking about Command Substitution? As in./dbot.sh $(python3 tragic.py)?
– PerlDuck
Mar 18 at 10:28
add a comment |Â
Some options for accomplishing this with various tools are discussed here.
– John1024
Mar 18 at 4:06
Are you talking about Command Substitution? As in./dbot.sh $(python3 tragic.py)?
– PerlDuck
Mar 18 at 10:28
Some options for accomplishing this with various tools are discussed here.
– John1024
Mar 18 at 4:06
Some options for accomplishing this with various tools are discussed here.
– John1024
Mar 18 at 4:06
Are you talking about Command Substitution? As in
./dbot.sh $(python3 tragic.py)?– PerlDuck
Mar 18 at 10:28
Are you talking about Command Substitution? As in
./dbot.sh $(python3 tragic.py)?– PerlDuck
Mar 18 at 10:28
add a comment |Â
1 Answer
1
active
oldest
votes
up vote
0
down vote
accepted
You can always use xargs, i.e.,
echo '-l' | xargs ls
will effectively execute ls -l. So in your case it should something like ./tragic.py | xargs ./dbot.sh, i.e., output of ./tragic.py command will be used as argument of ./dbot.sh
answered Mar 18 at 5:57
Jacek Herbrych
1716
Thanks for your help Jacek Herbrych - that is what i am looking for. I will give it a try! and thanks to John1024 and PerlDuck too.
– ethertec
Mar 18 at 17:43
add a comment |Â
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
accepted
You can always use xargs, i.e.,
echo '-l' | xargs ls
will effectively execute ls -l. So in your case it should something like ./tragic.py | xargs ./dbot.sh, i.e., output of ./tragic.py command will be used as argument of ./dbot.sh
answered Mar 18 at 5:57
Jacek Herbrych
1716
Thanks for your help Jacek Herbrych - that is what i am looking for. I will give it a try! and thanks to John1024 and PerlDuck too.
– ethertec
Mar 18 at 17:43
add a comment |Â
up vote
0
down vote
accepted
You can always use xargs, i.e.,
echo '-l' | xargs ls
will effectively execute ls -l. So in your case it should something like ./tragic.py | xargs ./dbot.sh, i.e., output of ./tragic.py command will be used as argument of ./dbot.sh
answered Mar 18 at 5:57
Jacek Herbrych
1716
Thanks for your help Jacek Herbrych - that is what i am looking for. I will give it a try! and thanks to John1024 and PerlDuck too.
– ethertec
Mar 18 at 17:43
add a comment |Â
up vote
0
down vote
accepted
up vote
0
down vote
accepted
You can always use xargs, i.e.,
echo '-l' | xargs ls
will effectively execute ls -l. So in your case it should something like ./tragic.py | xargs ./dbot.sh, i.e., output of ./tragic.py command will be used as argument of ./dbot.sh
answered Mar 18 at 5:57
Jacek Herbrych
1716
You can always use xargs, i.e.,
echo '-l' | xargs ls
will effectively execute ls -l. So in your case it should something like ./tragic.py | xargs ./dbot.sh, i.e., output of ./tragic.py command will be used as argument of ./dbot.sh
answered Mar 18 at 5:57
Jacek Herbrych
1716
answered Mar 18 at 5:57
Jacek Herbrych
1716
answered Mar 18 at 5:57
Jacek Herbrych
1716
answered Mar 18 at 5:57
Jacek Herbrych
1716
1716
Thanks for your help Jacek Herbrych - that is what i am looking for. I will give it a try! and thanks to John1024 and PerlDuck too.
– ethertec
Mar 18 at 17:43
add a comment |Â
Thanks for your help Jacek Herbrych - that is what i am looking for. I will give it a try! and thanks to John1024 and PerlDuck too.
– ethertec
Mar 18 at 17:43
Thanks for your help Jacek Herbrych - that is what i am looking for. I will give it a try! and thanks to John1024 and PerlDuck too.
– ethertec
Mar 18 at 17:43
Thanks for your help Jacek Herbrych - that is what i am looking for. I will give it a try! and thanks to John1024 and PerlDuck too.
– ethertec
Mar 18 at 17:43
add a comment |Â
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Some options for accomplishing this with various tools are discussed here.
– John1024
Mar 18 at 4:06
Are you talking about Command Substitution? As in
./dbot.sh $(python3 tragic.py)?– PerlDuck
Mar 18 at 10:28