How do I set a cron job for every 5 minutes without using the minutes divisible by 5?


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I have multiple cron jobs that I want to run every 5 minutes, some of which are memory intensive. As such, I don't want to run them all at the same time. Crontab lets me run a job that looks like
*/5 * * * * * <job>
which runs on the 0th, 5th, 10th, 15th, etc minutes. I'm looking for a way to run a cron job on the 2nd, 7th, 12th, 17th, etc minutes. Is there a way to do that without typing out every minute in that set?
cron
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up vote
1
down vote
favorite
I have multiple cron jobs that I want to run every 5 minutes, some of which are memory intensive. As such, I don't want to run them all at the same time. Crontab lets me run a job that looks like
*/5 * * * * * <job>
which runs on the 0th, 5th, 10th, 15th, etc minutes. I'm looking for a way to run a cron job on the 2nd, 7th, 12th, 17th, etc minutes. Is there a way to do that without typing out every minute in that set?
cron
add a comment |Â
up vote
1
down vote
favorite
up vote
1
down vote
favorite
I have multiple cron jobs that I want to run every 5 minutes, some of which are memory intensive. As such, I don't want to run them all at the same time. Crontab lets me run a job that looks like
*/5 * * * * * <job>
which runs on the 0th, 5th, 10th, 15th, etc minutes. I'm looking for a way to run a cron job on the 2nd, 7th, 12th, 17th, etc minutes. Is there a way to do that without typing out every minute in that set?
cron
I have multiple cron jobs that I want to run every 5 minutes, some of which are memory intensive. As such, I don't want to run them all at the same time. Crontab lets me run a job that looks like
*/5 * * * * * <job>
which runs on the 0th, 5th, 10th, 15th, etc minutes. I'm looking for a way to run a cron job on the 2nd, 7th, 12th, 17th, etc minutes. Is there a way to do that without typing out every minute in that set?
cron
asked Jun 2 at 0:04
SarcasticSully
163111
163111
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add a comment |Â
1 Answer
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up vote
2
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accepted
Answer to my own question
The answer to my question specifically is
2-59/5 * * * * <job>
In general, to run a job every nth minute starting at m (with 1â¤m<n), it's
m-59/n * * * * <job>
The dash means "every minute starting at m and ending at 59, inclusive on both ends."
add a comment |Â
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
2
down vote
accepted
Answer to my own question
The answer to my question specifically is
2-59/5 * * * * <job>
In general, to run a job every nth minute starting at m (with 1â¤m<n), it's
m-59/n * * * * <job>
The dash means "every minute starting at m and ending at 59, inclusive on both ends."
add a comment |Â
up vote
2
down vote
accepted
Answer to my own question
The answer to my question specifically is
2-59/5 * * * * <job>
In general, to run a job every nth minute starting at m (with 1â¤m<n), it's
m-59/n * * * * <job>
The dash means "every minute starting at m and ending at 59, inclusive on both ends."
add a comment |Â
up vote
2
down vote
accepted
up vote
2
down vote
accepted
Answer to my own question
The answer to my question specifically is
2-59/5 * * * * <job>
In general, to run a job every nth minute starting at m (with 1â¤m<n), it's
m-59/n * * * * <job>
The dash means "every minute starting at m and ending at 59, inclusive on both ends."
Answer to my own question
The answer to my question specifically is
2-59/5 * * * * <job>
In general, to run a job every nth minute starting at m (with 1â¤m<n), it's
m-59/n * * * * <job>
The dash means "every minute starting at m and ending at 59, inclusive on both ends."
answered Jun 2 at 0:20
SarcasticSully
163111
163111
add a comment |Â
add a comment |Â
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